Asked by Terry
y= (t^3 + t)/(t^4 - 2)
y'=
y'=
Answers
Answered by
JJ
This is derivative of a division (fraction.
the rule is
the denominator times the derivative of the numerator - the numerator times the derivative of the denominator.
ALL OVER the denominator squared.
The denominator of the derivative is the easy part. It is just (t^4 -2)^2
Now.. lets work on the other part.
(t^4 -2)(3t^2+1)-(t^3+t)(4t^3)
You have to multiply and simplify the numerator and put it over the denominator. Be careful of the negative signs.
the rule is
the denominator times the derivative of the numerator - the numerator times the derivative of the denominator.
ALL OVER the denominator squared.
The denominator of the derivative is the easy part. It is just (t^4 -2)^2
Now.. lets work on the other part.
(t^4 -2)(3t^2+1)-(t^3+t)(4t^3)
You have to multiply and simplify the numerator and put it over the denominator. Be careful of the negative signs.
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