Asked by Jim
State the value of the discriminant and the number of real solutions.
t^2+14t+49=0
The value of the discriminant is 0 and the equation has no real solution.
t^2+14t+49=0
The value of the discriminant is 0 and the equation has no real solution.
Answers
Answered by
Reiny
No
If the discriminant is zero, then the quadratic factors to a perfect square, and there will be one real solution (actually two real but equal solutions)
t^2+14t+49=0
(t+7)^2 = 0
t+7 = 0
t = -7
If the discriminant is zero, then the quadratic factors to a perfect square, and there will be one real solution (actually two real but equal solutions)
t^2+14t+49=0
(t+7)^2 = 0
t+7 = 0
t = -7
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