Asked by Sara
Find the integral of:
(x+2)/(x^3+2x^2-3x)dx
(x+2)/(x^3+2x^2-3x)dx
Answers
Answered by
Steve
since x^3+2x^2-3x = x(x+3)(x-2), use partial fractions to get an equivalent:
3/(4(x-1)) - 2/(3x) - 1/(12(x+3))
That easily integrate into
3/4 log(x-1) - 2/3 log(x) - 1/12 log(x+3)
which you can massage as you will.
3/(4(x-1)) - 2/(3x) - 1/(12(x+3))
That easily integrate into
3/4 log(x-1) - 2/3 log(x) - 1/12 log(x+3)
which you can massage as you will.
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