Question

(3a^2+6ab-a-2b)/(9a^2-6a+1)

Answer 1

OK - one more freebie. After this, show some work and we'll see how you're doing.

3a^2+6ab-a-2b = 3a^2-a + 6ab-2b
= a(3a-1) + 2b(3a-1) = (a-2b)(3a-1)

9a^2-6a+1 = (3a-1)(3a-1)

divide and you have (a-2b)/(3a-1)

Answer 2

The numerator, you have to factor by grouping.

Group: (3a^2 + 6ab) + (-a -2b)
Take out the common factor in each group and then you should see two identical factors. Write that factor down once and your second factor is what is left over (actually, what you factored out from each part.)

The denominator can be factored as a perfect square.

You should be able to cancel out like factors to reduce the fraction.