Consider the following equilibrium at 395K: NH4HS(s)<-> NH3(g) + H2S(g) The partial pressure of each gas is 0.265 atm. Calculate Kc for the reaction.

2 answers

Kp = pNH3*pH2S
Substitute partial pressures and solve for Kp. Then convert Kp to kc by
Kp = Kc*RTdelta n
Note that I omitted some parentheses.
Kp = Kc*(RT)delta n
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