Asked by Cami
Consider the following equilibrium at 395K:
NH4HS(s) <--> NH3(g) + H2S(g)
The partial pressure of each gas is 0.265 atm. Calculate Kc for the reaction
NH4HS(s) <--> NH3(g) + H2S(g)
The partial pressure of each gas is 0.265 atm. Calculate Kc for the reaction
Answers
Answered by
DrBob222
Kp = pNH3*pH2S
Then Kp = Kc(RT)^delta n
Then Kp = Kc(RT)^delta n
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