Find the average rate of change for function f(x)=3x^(2)-5 at the points x[1]=6 and x[2]=10

Answer 1

avg rate of change is ∆y/∆x for the interval

∆y = f(10)-f(6) = 295-103 = 192
∆x = 10-6 = 4

avg rate of change is thus 192/4 = 48