Asked by Anonymous
Find the average rate of change for function f(x)=3x^(2)-5 at the points x[1]=6 and x[2]=10
Answers
Answered by
Steve
avg rate of change is ∆y/∆x for the interval
∆y = f(10)-f(6) = 295-103 = 192
∆x = 10-6 = 4
avg rate of change is thus 192/4 = 48
∆y = f(10)-f(6) = 295-103 = 192
∆x = 10-6 = 4
avg rate of change is thus 192/4 = 48
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