Asked by Jacob

Find the derivative of the function:

(x^(3)-8)/(x^(2)+9)
Answered by JJ
The rule is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator AND then put this answer over the denominator squared.

The deriv. of the numerator is 3x^2 and the deriv of the denom. is 2x

Can you finish from here?
Answered by Steve
y = (x^3-8)/(x^2+9)
If y = u/v, y' = (vu' - uv')/v^2, so

y = ((3x^2)(x^2+9) - (x^3-8)(2x))/(x^2+9)^2

= (3x^4 + 27x^2 - 2x^4 + 16x)/(x^2+9)^2

= (x^4 + 27x^2 + 16x)/(x^2+9)^2
Answered by Jacob
Yeah, I was forgetful and forgot it was the Quotient Rule. Thank you all, I got it!
Answered by Steve
just curious -- if you forgot about the quotient rule, what did you try?
Answered by no
this web site dead kinda
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