Asked by Olivia

How many grams of oxygen are collected in a reaction where 247 mL of oxygen gas is collected over water at a temperature of 25°C and a total pressure of 697 torr?
Answered by DrBob222
Use PV = nRT and solve for n.
P = (697-vapor pressure H2O @ 25C/760)
V = 0.247 L
T = 298 K
n = number of mols. Then n = grams/molar mass. You know molar mass and n, solve for grams.
Answered by Olivia
So would i just convert 697 torr into atm and use that for pressure? or what do i do with the 25C/760?
Answered by DrBob222
It isn't 25C/760.
See the later post where I broke this down. If you still have trouble, repost and make a note about what you don't understand.
Ptotal = pgas + pH2O
697 = pgas + vapor pressure H2O @ 25C.
Solve for pgas. Then divide that number by 760 to convert to atm.
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