Asked by Felipe
how many grams of oxygen are in 213.5g Fe2O3?
Answers
Answered by
DrBob222
213.5g Fe2O3 x (1 mole Fe2O3/molar mass Fe2O3) x (3 atoms oxygen/1 mole Fe2O3) x (16 g oxygen/1 mole O atoms) =
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.