Question

How many grams of oxygen gas can be produced when 4.50 L of NO2 react according to the equation below at 427 ¨¬C and 1.15 atm?

4NO2(g) + 6H2O(g) ¡æ 7 O2(g) + 4NH3(g)

Answer 1

first figure the moles of NO2 (use the ideal gas law).

then you get 7/4 moles O2 for each mole of NO2. Change that to grams O2