Asked by Chris
Three circles with radii of 4, 5, and 6 cm, respectively, are tangent to each other externally. Find the angles of the triangle whose vertexes are the centers of the circles.
Answers
Answered by
bobpursley
sides of triangle are (2+2.5),(2+3),(2.5+3)
Start with law of cosines
c^2=a^2+b^2-2abCosC
label the sides a,b, c solve for angle C
Then, use the law of sines
a/SinA=c/SinC solve for angle A
then use the fact that the sum of the angles is 180 deg, find angle B.
check angle B with the law of sines.
Start with law of cosines
c^2=a^2+b^2-2abCosC
label the sides a,b, c solve for angle C
Then, use the law of sines
a/SinA=c/SinC solve for angle A
then use the fact that the sum of the angles is 180 deg, find angle B.
check angle B with the law of sines.
Answered by
Anonymous
474
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