Asked by Phil

A small object of mass 2.60 g and charge -17 µC "floats" in a uniform electric field. What is the magnitude and direction of the electric field?
Answered by drwls
Solve
Q*E = M*g
to get the field, E. The units will be Newtons per Coulomb

The direction of the E field must be down, so that the electrostatic force on the negative particle will be up.
Answered by ben
2.60*17
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