I do not know what your problem is. That is sort of the quadratic equation:
x = [-b +/- sqrt(b^2-4ac)]/2a
and you would get the two answers but I did not see the original quadratic so do not know if right or not (although I can do it backwards).
I need to know if I need to further reduce my answer or if I leave it the way I have it. I have the original problem and then my answer.
-b +or- sqrt b^2=4ac/2a
answer x= -1/2 +or- 1/10
3 answers
now to do it backwards
if x = -.5 and x = -.1 are solutions then
(x+.5)(x+.1) = 0
x^2 + .6 x + .05 = 0
100 x^2 + 60 x + 5 = 0
if x = -.5 and x = -.1 are solutions then
(x+.5)(x+.1) = 0
x^2 + .6 x + .05 = 0
100 x^2 + 60 x + 5 = 0
oh,divide by 5
20 x^2 + 12 x + 1 = 0
20 x^2 + 12 x + 1 = 0