Asked by Mike


The ΔHvap of a certain compound is 34.68 kJ·mol–1 and its ΔSvap is 93.60 J·mol–1·K–1. What it the boiling point of this compound?
Answered by DrBob222
dG = dH - TdS
dG = 0
dH = 34,680 J
dS = 93.6
Solve for T (in kelvin).
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