Asked by Hannah
A certain first-order reaction has a rate constant of 2.75 10-2 s−1 at 20.°C. What is the value of k at 50.°C if Ea = 75.5 kJ/mol?
i know to use the ln(k1/k2)= (ea/R)((1/T1)-(1/T2)) but how do i know what T2 is when i only have one temp?
there is a b part to the question
(b) Another first-order reaction also has a rate constant of 2.75 10-2 s−1 at 20.°C. What is the value of k at 50.°C if Ea = 125 kJ/mol?
do i have to use this info to hellp me get a?
i know to use the ln(k1/k2)= (ea/R)((1/T1)-(1/T2)) but how do i know what T2 is when i only have one temp?
there is a b part to the question
(b) Another first-order reaction also has a rate constant of 2.75 10-2 s−1 at 20.°C. What is the value of k at 50.°C if Ea = 125 kJ/mol?
do i have to use this info to hellp me get a?
Answers
Answered by
DrBob222
You have typed the wrong equation. It is
ln(k2/k1) = (Ea/R)(1/1 - 1/T2)
I see two Temps in the probloem. 20C and 50C.
ln(k2/k1) = (Ea/R)(1/1 - 1/T2)
I see two Temps in the probloem. 20C and 50C.
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