Asked by student
A certain first order reaction has a rate constant of 3.75x10^-2 s^-1 at 25.0C. What is the value of k at 70.0C when the activation energy is 135 kj/mol?
Would I use the formula K=Ae ^-Ea/RT even though I have two temperatures?
Would I use the formula K=Ae ^-Ea/RT even though I have two temperatures?
Answers
Answered by
DrBob222
I would use ln(k2/k1) = Ea/R(1/T1 - 1/T2)
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