Asked by Assignment2
A first order reaction is 40% complete after 8minute, how long will it take for 1/4 of the reactant to be used up.
Answers
Answered by
DrBob222
ln(No/N) = kt
ln(100/60) = k*8
Solve for k, then substitute k into
ln (100/25) = k from above (t)
Solve for t in minutes
ln(100/60) = k*8
Solve for k, then substitute k into
ln (100/25) = k from above (t)
Solve for t in minutes
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