Asked by Darcy
A first order reaction has an activation enery of 50.0kJ/mol. When a catalyst is added the activation energy of the catalyzed reaction is Ea/2. Calculate the ration of k(uncatalyzed)/k(catalyzed) at 25 degree C.
Answers
Answered by
DrBob222
I looked at this but didn't finish. I was looking at ln k = -Ea/(RT) + ln(A).
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