Asked by Heidi
A downward force of 5.1 N is exerted on a -7.3 mcirco C charge. What is the magnitude of the electric field at this point?
Answers
Answered by
Samir
E=F/q so E=(5.1N)/(7.3x10^-6 C)
= 6.99x10^5 N/C
7.3 microC = 7x10^-6 C
= 6.99x10^5 N/C
7.3 microC = 7x10^-6 C
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.