Question
A downward force of 5.1 N is exerted on a -7.3 mcirco C charge. What is the magnitude of the electric field at this point?
Answers
Samir
E=F/q so E=(5.1N)/(7.3x10^-6 C)
= 6.99x10^5 N/C
7.3 microC = 7x10^-6 C
= 6.99x10^5 N/C
7.3 microC = 7x10^-6 C