Answers by visitors named: Heidi

WHAT DO YOU MEAN MORE KNEADING? and that would cause it to become harder right and not as runny? so if I kneaded less it would be runnier? if so why is this?

30. Using the midpoint method of elasticity to calculate price elasticity of demand eliminates the problem of ______. (Points: 3) different elasticities, depending on whether price decreases or increases I PICKED THIS ONE different elasticities because price and quantity are inversely related on the demand curve total revenue falling when price falls and demand is inelastic total revenue increasing when price falls and demand is elastic

Need help with this paper

thanks so much

Maya Angelou was a singer, actor, civil rights worker, journalist, and director. She was been through so much and has transcended into one of the world’s most famous authors. Out of all her past occupations, she is best known for her literary works.

When a student has chosen to continue their education, they have started towards being financially secure in life. Is that better?

or this... When a student has chosen to continue his or her education, her or she has started towards being financially secure in life.

Thank you very much!!! The verb tenses are both present perfect?

MLA has updated. Now you have to include what sort of medium was used. in this case you should end with Print if a print source or Web if a web source. The other piece might be in the teacher asked you to include the url.

I know you asked this 6 years ago, but someone may learn something from this answer: You have a peculiar set of inputs and outputs. The first two especially should give you a hint: they're the same! 0 squared is 0; similarly, 1 squared is 1. If you square your other inputs, you'll see they're the same way. Your fill-in-the-blank sentence is given a hint in the next sentence: a function has only one output for each input, that is, you won't input 3 and get both 6 and 10. So your sentence is "yes, because for each input there is exactly one output."

Thank you so much... Huge help

brick= (3/4)+(3/4) brick=(6/4)=1.5

A unbiased die is thrown seven times. Find the probability of throwing at least five six's.

It is the formula my teacher gave me so I suppose that's what I'm supposed to do. Thank you.

dB x distance^2 = K 120dB x 10^2 = 85dB X d^2 Divide both sides by 85dB 141 = d^2 11.874342087 You should sit 11.87 meters from the band for the sound level to be 85dB.

225g

Do you just take the absolute value for pH 6? @DrBob222

How many moles of conjugate base (Na2HPO4) are present in 40mL of .010M buffer at pH 7.5 vs at pH 6? Buffer was made up of Na2HPO4 and NaH2PO4. pH=pKa +log[A/HA]; pKa=7.2.... When I did the calculations I got the same amount as if it were in a 0.1M buffer at the same pH's so I think I'm doing something wrong.

Ignore the second post at 10:32, I'm going to post it as it's own question!

@Dr.Bob222 I guess I'm still not following what you're saying. Following the above method I got a=3.76 and b=.237. If I were to subtract the .5 I would get -.263 for HPO4 and 4.26 for H2PO4 (added obviously). I understand a negative number is showing excess HCl but I don't understand what you're talking about with M HCL mmols/mL and what to do from there.

Not to mention I also have to do this for 40mL of a .01M and all those will be negative following the same steps. I understand that 1M(mole/L) is the same as 1mmol/mL but I don't see how that helps as well. @DrBob222

@DrBob222 oh, so instead of solving for change in pH we stop after a+b=4mmols. so it'll be different when it goes to .01M. But 7.5=7.2+logb/a; b=2a a+b=.004mols; 3a=.004 a=.00376 b=.000237. So that would be my final answer for pH 7.5 and I do the same for pH 6?

And, the whole pH 6 thing still doesn't make sense. I just took the absolute value and got a change in pH of .0095.

So .24/40=.006 7.2+log[.006/4.26]=4.35 so that's a huge change in pH (1.47). Which makes sense because there's excess HCl. expected pH of a substance. So

@DrBob222, would I follow this same format if I wanted to find predicted pH with the pH correction factors. for example, I would expect a solution I made with ideal pH 7.5 to have a pH of pH=7.2+log(2.2/1.8)+log(.45/.74)=7.07. Correction factors were given to us. But now looking at pH 6, that doesn't make sense because the expected value of that would be 4.13 which is not even close to what we measured. Did I do something wrong again?

@DrBob222 Ahh. So I can't use this calculation to calculate the pH with the addition of a phosphate buffer correction factor? Because I'm asked to calculate the pH using phosphate correction factor when 0.50ml of 1M HCl is added to 40mL of .10M buffer at expected pH 6 and pH 6.5. So same numbers as above. I know the correction factors: Correction factors for .10M: HPO4-0.45 H2PO4-0.74 but since I don't have a ratio to plug into the equation I can't do that? I used the same method we did for pH 7.5 fo 6.5 and got funky numbers as well.

Temperature is at 25C, I forgot to add that!

d as in derivative? How would I factor in the 2L though? That's also throwing me off.

d=difference. Wow, okay- makes more sense now.

I was thinking this entire time 2L meant two liters. My professor just didn't put a space between the 2 and the L. L has nothing to do with the two, it has to do with the compound itself.

Thank you! I would've been able to handle this problem without any help if I had realized it 2=n instead of 2L.

Thank you so much! This helped a lot!

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I really don’t know I’m only in 5th grade. 🙂

I hope I will find it Ireally do not like social studies. so give me hope

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