what power is expended by a weightlifter when lifting a 60kg barbell a vertical distance of 1.1m in a time interval of 2.0s

Answer 1

Fb = m*g = 60kg * 9.8N/kg = 588 N. =
Force of the barbell.

Power = F*d/t = 588*1.1/2=323.4 Joules/s
= 323.4 Watts.