Asked by Joyce
what power is expended by a weightlifter when lifting a 60kg barbell a vertical distance of 1.1m in a time interval of 2.0s
Answers
Answered by
Henry
Fb = m*g = 60kg * 9.8N/kg = 588 N. =
Force of the barbell.
Power = F*d/t = 588*1.1/2=323.4 Joules/s
= 323.4 Watts.
Force of the barbell.
Power = F*d/t = 588*1.1/2=323.4 Joules/s
= 323.4 Watts.
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