Asked by Ashley
                The blood speed in a normal segment of a horizontal artery is 0.166 m/s. An abnormal segment of the artery is narrowed down by an arteriosclerotic plaque to 1/5 of its normal cross-sectional area. What is the difference in blood pressure between the normal and constricted segments of the artery?
            
            
        Answers
                    Answered by
            Damon
            
    1/5 of the area ----> 5 times the speed
if the same amount passes each point in a second (continuity)
p + (1/2) rho v^2 = constant says Mr Bernoulli
P1 + (1/2) rho v^2 = P2 + (1/2) rho (5 v)^2
P1 - P2 = (1/2) rho (25-1)v^2
rho is approximately that of water 1000 kh/m^3
and v is .166 m/s
so
P1-P2 = 500 (24)(.166)^2
    
if the same amount passes each point in a second (continuity)
p + (1/2) rho v^2 = constant says Mr Bernoulli
P1 + (1/2) rho v^2 = P2 + (1/2) rho (5 v)^2
P1 - P2 = (1/2) rho (25-1)v^2
rho is approximately that of water 1000 kh/m^3
and v is .166 m/s
so
P1-P2 = 500 (24)(.166)^2
                    Answered by
            Ashley
            
    Thanks! blood's density is 1060 kg/m^3 but it worked perfectly! and makes sence
    
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