Asked by Prisca
The concentration of k ions inside the nerve cell is about 20 times greater than concentration of these ions outside the nerve cell.what potential difference between outside and inside of the cell would you expect to measure if ths was only due to the concentration difference of potassium ions?
Answers
Answered by
Devron
Use the Nernst equation:
E=(RT/zF)ln([K+]o/[K+]i)
E=(RT/zF)ln([K+]o/[K+]i)
Answered by
Prisca
Mind illustrating how??
Answered by
Devron
Okay, I am assuming that this is at 25ยบ C
R=8.314 J.K-1.mol-1
F=96485 C.mol-1
T=25+273.15
z=+1
[K+]o=1
[K+]i=20
E=(RT/zF)ln([K+]o/[K+]i)
E=(8.314 *298/(1*96485)ln(1/20)
E=61ln(1/20)=-183mV
R=8.314 J.K-1.mol-1
F=96485 C.mol-1
T=25+273.15
z=+1
[K+]o=1
[K+]i=20
E=(RT/zF)ln([K+]o/[K+]i)
E=(8.314 *298/(1*96485)ln(1/20)
E=61ln(1/20)=-183mV
Answered by
Prisca
Thank u so much:)
There are no AI answers yet. The ability to request AI answers is coming soon!