Asked by rroyd
Simplifying exponents 4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n))
Answers
Answered by
Reiny
When factoring always take out the power with the smaller of the exponents
4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n))
= 2(5^(2n-1) ) ( 2(5^2 - 5(1) )/2(5^n))
= 5^(n-1) (50 - 5)
= 225 (5^(n-1) )
4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n))
= 2(5^(2n-1) ) ( 2(5^2 - 5(1) )/2(5^n))
= 5^(n-1) (50 - 5)
= 225 (5^(n-1) )
Answered by
rroyd
PLease explain furter a little the steps of this...
4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n))
= 2(5^(2n-1) ) ( 2(5^2 - 5(1) )/2(5^n))
= 5^(n-1) (50 - 5)
= 225 (5^(n-1) )
4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n))
= 2(5^(2n-1) ) ( 2(5^2 - 5(1) )/2(5^n))
= 5^(n-1) (50 - 5)
= 225 (5^(n-1) )