Ask a New Question
Search
Questions and answers by
rroyd
Questions (2)
Please explain a little bit further
4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n)) = 2(5^(2n-1) ) ( 2(5^2 - 5(1) )/2(5^n)) = 5^(n-1) (50 -
0 answers
845 views
Simplifying exponents 4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n))
2 answers
407 views
Answers (1)
PLease explain furter a little the steps of this... 4(5^(2n+1))-10(5^(2n-1))/ ( 2(5^n)) = 2(5^(2n-1) ) ( 2(5^2 - 5(1) )/2(5^n)) = 5^(n-1) (50 - 5) = 225 (5^(n-1) )
