Asked by Ted
A pendulum bob is released from some initial
height such that the speed of the bob at the
bottom of the swing is 1.5 m/s.
The acceleration of gravity is 9.81 m/s
2
.
What is the initial height of the bob?
Answer in units of m
height such that the speed of the bob at the
bottom of the swing is 1.5 m/s.
The acceleration of gravity is 9.81 m/s
2
.
What is the initial height of the bob?
Answer in units of m
Answers
Answered by
bobpursley
Initial PE=final KE at bottom
mgh=1/2 mv^2
solve for h.
mgh=1/2 mv^2
solve for h.
Answered by
bvnbvn
gnghn
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