Question
A student wants to prepare Halite. How much sodium can he use to completely react it with 30g of Chlorine gas?
Answers
Devron
Na +Cl---> NaCl
30g of Cl*(1 mole of Cl/35.45 g of Cl)= moles of Cl
Since moles of Cl=moles of Na
moles of Na *(22.99 g of Na/1 mole of Na)= g's of Na needed to react with chlorine gas
30g of Cl*(1 mole of Cl/35.45 g of Cl)= moles of Cl
Since moles of Cl=moles of Na
moles of Na *(22.99 g of Na/1 mole of Na)= g's of Na needed to react with chlorine gas