85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution

How would I do this, given 2 volumes?

Question

85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution.

Using the formula C(Concentration)=n(moles)/v(Volume measured in litres.)

How am I supposed to solve this question given two volumes?

Anonymous · Answer

use M1V1=M2V2
the C=M
That formula is just telling you what concentration is.
In the formula i mention M1 is the initial concentration and V1 is the initial volume. M2 is the final concentration. V2 is the final volume. You are solving for M2.

AlphaPrimes · Answer

Oh, that makes sense. Thanks!

AmbiguousCase · Answer

85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution How would I do this, given 2 volumes?