Asked by Julia
The launching speed of a certain projectile is 9.0 times the speed it has at its maximum height. Calculate the elevation angle at launching.
Answers
Answered by
Damon
at start u = u forever
Vi = Vi
u^2 + Vi^2 = 81 u^2
so
Vi^2 = 80 u^2
Vi = 8.94 u
tan A = Vi/u = 8.94
so
A = 83.6 degrees above horizontal
Vi = Vi
u^2 + Vi^2 = 81 u^2
so
Vi^2 = 80 u^2
Vi = 8.94 u
tan A = Vi/u = 8.94
so
A = 83.6 degrees above horizontal
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.