There are lots of possible approximations. If we have
y = x^5, the slope of the tangent line is
y' = 5x^4
At (2,32), the slope is 80
so, if a(x) is the line,
a(x) = 80(x-2)+32
a(2.04) = 80(.04)+32 = 35.2
In fact, 2.04^5 = 35.33
STATE THE LINEAR APPROXIMATION FOR: (2.04)raise to power 5
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