Question
The linear approximation at x = 0 to f(x) = \sqrt { 3 + 3 x } is y =
Please Help!
Please Help!
Answers
Steve
y = √(3x+3)
y' = 3/(2√(3x+3))
y'(0) = 3/(2√3)
at x=0, y=√3
SO, now we have a point and a slope. The tangent line at x=0 is
y = 3/(2√3) x + √3
For x near zero, the line is very close to the curve
y' = 3/(2√(3x+3))
y'(0) = 3/(2√3)
at x=0, y=√3
SO, now we have a point and a slope. The tangent line at x=0 is
y = 3/(2√3) x + √3
For x near zero, the line is very close to the curve