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Asked by doruntina

be found arithmetic series
3a2-a6=-a2
a3+a4=19
12 years ago

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Answered by bobpursley
an=ao +n*d

a2=ao+2d
a6=ao+6d
a3=ao+3d
a4=ao+3d

substutite all those, and find ao, and d.
12 years ago
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be found arithmetic series
3a2-a6=-a2
a3+a4=19

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