Asked by Fernando
An arithmetic series is such that the 10th term is 40 and the sum of the first 10 terms is 265. Find the sum of the first 20 terms.
Answers
Answered by
Steve
T10 = a+9d = 40
S10 = 10/2 (a+40) = 265
a = 13
so, d=3
S20 = 20/2 (2*13+19*3) = 830
S10 = 10/2 (a+40) = 265
a = 13
so, d=3
S20 = 20/2 (2*13+19*3) = 830
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