Asked by Joseph
A rectangle was 25 cm longer than it was wide. A new rectangle was formed by decreasing the length by 6 cm and decreasing the width by 5 cm. The area of the new rectangle was 585 cm squared. Find the dimensions of the original rectangle.
Answers
Answered by
Reiny
original:
width --- x
length -- x+25
new one:
width --- x-5
length --- x+25-6 = x+19
(x-5)(x+19) = 585
x^2 + 14x - 95 = 585
x^2 + 14x - 680 = 0
(x-20)(x+34) = 0
x = 20 or x is a negative, which would be bogus
original
width is 20 and length is 45
width --- x
length -- x+25
new one:
width --- x-5
length --- x+25-6 = x+19
(x-5)(x+19) = 585
x^2 + 14x - 95 = 585
x^2 + 14x - 680 = 0
(x-20)(x+34) = 0
x = 20 or x is a negative, which would be bogus
original
width is 20 and length is 45
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