Asked by Anonymous

A rectangle is 12in longer than it is wide. The perimeter is 68m. Write an equation and show steps to find its length and width.

I need help figuring out what the equation would be. I found out that the length is 23 in and the width is 11 in, but I can't figure out how to make it into an equation.

Answers

Answered by Ms. Sue
P = 2L + 2W
68 = (2 * 23) + (2 * 11)
Answered by Bosnian
A rectangle is 12 in longer than it is wide mean:

L = W +12

Perimeter:

P = 2 L + 2 W = 2 ( L + W ) = 2 ( W + 12 + W ) = 2 ∙ ( 2 W + 12 )

P = 4 W + 24

68 = 4 W + 24

Subtract 24 to both sides

68 - 24 = 4 W + 24 - 24

44 = 4 W

Divide both sides by 4

44 / 4 = W

11 = W

W = 11 in

L = W +12 = 11 + 12 = 23 in
Answered by Anonymous
I also need to incorporate that the length is 12 more than the width into the equation, though.
Answered by Anonymous
Thank you Bosnian
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