mols = M x L = ?
mol = grams/molar mass. You know molar mass and mols, solve for grams.
How many grams of AgNO3 (silver nitrate) are contained in 425 mL of a .15 M solution of AgNO3?
3 answers
i don't understand...
You can't understand if you don't try. You could help by explaining exactly what you don't understand instead of leaving me hanging out there with no idea of which direction to go to help.
mols = M x L. You have M = 0.15M in the problem. You have 425 mL (0.425L) volume in the problem. 0.425L x 0.15M = ? mols AgNO3. You can multiply that on your calculator.
Then mols AgNO3 = grams AgNO3/molar mass AgNO3. You have mols from the previous line. You know molar mass AgNO3. Substitute those two values and solve for grams AgNO3. That's the answer.
mols = M x L. You have M = 0.15M in the problem. You have 425 mL (0.425L) volume in the problem. 0.425L x 0.15M = ? mols AgNO3. You can multiply that on your calculator.
Then mols AgNO3 = grams AgNO3/molar mass AgNO3. You have mols from the previous line. You know molar mass AgNO3. Substitute those two values and solve for grams AgNO3. That's the answer.