Asked by Barbara
How many grams of AgNo3 are required to make 25 mL of a .80M solution?
Answers
Answered by
DrBob222
M = moles/L
Substitute L and M, solve for moles.
moles = grams/molar mass
Substitute moles and molar mass and solve for grams.
Substitute L and M, solve for moles.
moles = grams/molar mass
Substitute moles and molar mass and solve for grams.
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