Question

Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

Answer 1

p+n+d = 140
n = 2p-12
d = 3p-22

(p,n,d) = (29,46,65)

Answer 2

Thank you !