Asked by Brittney

Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 19 less than three times the number of pennies. How many coins of each kind does she have?
Answered by helper
p = pennies
2p - 9 = nickles
3p - 19 = dimes

p + 2p - 9 + 3p - 19 = 140
6p - 28 = 140
6p = 168
p = 28

p = pennies = 28
2p - 9 = nickles = 47
3p - 19 = 65
Answered by Lisa
there are 100 coins. ten are dimes. the rest are pennies and nickles. there are twice as many pennies as nickles. how many pennies and nickles are in the jar?
Answered by Chanelle
Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?