Asked by Anonymous
A milk tanker cylinderical in shape having a diameter of 2m and height 4.2m supplies milk to the two booths in the ratio3:2 .One of the milk booths having arectangular base area of 3.96 sq. m and the other has a cylinderical vessel having diameter of 2m. Find the level of milk in each vessel..
Answers
Answered by
Damon
3/5 to rectangular tank
2/5 to cylinderical tank
volume of tanker = pi r^2 H = pi d^2/4 h
= pi (4/4)(4.2) = 13.2 m^3
(3/5 )13.2 = 7.92 m^3 = 3.96 h
so h = 2 meters
(2/5 )13.2 = 5.28 m^3
5.28 = pi (4/4) h
h = 1.68 meter
2/5 to cylinderical tank
volume of tanker = pi r^2 H = pi d^2/4 h
= pi (4/4)(4.2) = 13.2 m^3
(3/5 )13.2 = 7.92 m^3 = 3.96 h
so h = 2 meters
(2/5 )13.2 = 5.28 m^3
5.28 = pi (4/4) h
h = 1.68 meter
Answered by
oluchi
vol of cylinder=pie*r^2*h
(22/7)*1^2*4.2=13.2
rectangula booth==>3 of 5 parts
(3/5)*13.2=7.92m
cyliderical booth recives 13.2-7.92=5.28m
(22/7)*1^2*4.2=13.2
rectangula booth==>3 of 5 parts
(3/5)*13.2=7.92m
cyliderical booth recives 13.2-7.92=5.28m
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