Asked by Alyssa
A cylinderical brass rod with a radius of 2.10 cm and length of 1.50 m is placed in a fire with temperature of 490 deg. C. If the other end of the rod is at a temperature of 33 deg. C, what is the rate of heat transfer through the rod (ignore any heat loss from the sides of the rod).
Brass constant = 110
Brass constant = 110
Answers
Answered by
bobpursley
I assume you mean for Brass constant, the thermal conductivity for brass is 100Watts/mK
Heat flow=100watt/m k * Area*(deltaT)/length
= 100watt/mK * .0105^2m^2(490-33)K/1.5m
= you do the math.
Heat flow=100watt/m k * Area*(deltaT)/length
= 100watt/mK * .0105^2m^2(490-33)K/1.5m
= you do the math.
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