A cylinderical brass rod with a radius of 2.10 cm and length of 1.50 m is placed in a fire with temperature of 490 deg. C. If the other end of the rod is at a temperature of 33 deg. C, what is the rate of heat transfer through the rod (ignore any heat loss from the sides of the rod).

Brass constant = 110

1 answer

I assume you mean for Brass constant, the thermal conductivity for brass is 100Watts/mK

Heat flow=100watt/m k * Area*(deltaT)/length
= 100watt/mK * .0105^2m^2(490-33)K/1.5m

= you do the math.