Asked by christ
Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius
Answers
Answered by
Elena
KE(tr) =3kT/2= ....
k=1.38•10⁻²³ J/K,
T=273+27=300 K.
k=1.38•10⁻²³ J/K,
T=273+27=300 K.
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