Asked by christ
A string of natural length L extends to a new length L' under tensile force F. If Hooke’S law applies, the work done in stretching the spring is ------------
Answers
Answered by
Elena
F=kx=k(L-L`)
k=F/(L-L`)
W=kx²/2= F (L-L`)²/2(L-L`)= F (L-L`)/2.
k=F/(L-L`)
W=kx²/2= F (L-L`)²/2(L-L`)= F (L-L`)/2.
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