Question
An animal-rescue plane flying due east at 36.0 m/s drops a bale of hay from an altitude of h = 69.5 m, as shown below. If the bale of hay weighs F = 162 N, what is the momentum of the bale the moment before it strikes the ground? Give both magnitude and direction.
Answers
Anonymous
weight=mg
mg*h= GPE(initial)=KE(final)=1/2mv^2
(2*mgh)^1/2=mv=momentum=(2*(162N)(69.5m))^1/2= 150 N s
mg*h= GPE(initial)=KE(final)=1/2mv^2
(2*mgh)^1/2=mv=momentum=(2*(162N)(69.5m))^1/2= 150 N s