Asked by Bridge
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. Assume the plane is traveling horizontally with a speed of 195 km/h (54.2 m/s).
How far in advance of the recipients (horizontal distance) must the goods be dropped
How far in advance of the recipients (horizontal distance) must the goods be dropped
Answers
Answered by
Damon
time to fall
235 = .5 g t^2 = 4.9 t^2
so t = 6.93 seconds
horizontal distance = 54.2*6.93
235 = .5 g t^2 = 4.9 t^2
so t = 6.93 seconds
horizontal distance = 54.2*6.93
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