Asked by Jake
The area of certain rectangle is 288 yd. the perimeter is 68 yd. if you double the length and width, what will be the area and perimeter of the new rectangle.
Answers
Answered by
PsyDAG
L * W = 288
W = 288/L
2L + 2W = 68
Substitute 288/L for W in last equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the last equation.
W = 288/L
2L + 2W = 68
Substitute 288/L for W in last equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the last equation.
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