Asked by Anonymous
What is the area of a rectangle with 4.5 for diagonals and 4 for width
Answers
Answered by
MsPi_3.14159265
You need to use the pythagorean theorem to find length of the base. c<sup>2</sup> = a<sup>2</sup> +b<sup>2</sup>
Then use (bxh)/2 to find the area
Then use (bxh)/2 to find the area
Answered by
Anonymous
back from my break.
I'm not sure if I put the values in their correct spots in the Pythagorean theorem correctly but,
4^2 + 4.5^2 = 36.25
(bxh)/2
(36.25 * 4) / 2 = 72.5
I'm not sure if I put the values in their correct spots in the Pythagorean theorem correctly but,
4^2 + 4.5^2 = 36.25
(bxh)/2
(36.25 * 4) / 2 = 72.5
Answered by
Henry
h^2 + W^2 = (4.5)^2.
W = 4.
h = ?
Area = h * W.
W = 4.
h = ?
Area = h * W.
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