tan60 = Y/X1 = 150/X1.
X1 = 150/tan60 = 86.6 m. = Dist. from
1st boat to bottom of cliff.
tan30 = Y/X2 = 150/X2.
X2 = 150/tan30 = 259.8 m. = Dist. from 2nd boat to bottom of cliff.
X = X1 + X2 = 86.6 + 259.8 = 346.4 m. = Dist. between the two boats.
From the top of a cliff 150m high, the angles of depression of two boats are 60 and 30. Find the distance between the boats if they are on the opposite sides of the cliff.
1 answer