Asked by Bobby
a 40 kg high jumper leaves the ground with a speed of 6m/s. how high can he jump ?
Answers
Answered by
drwls
The mass does not matter. The jumper's center of mass can be raised an amount H that is given by
gH = V^2/2,
assuming yjat the initial velolcity V is UP.
Thus H = V^2/(2g) = 1.84 m = 6 ft 5 inches
The actual high jump world record is higher than that (about 8 feet)because the center of mass does not start at the ground, and because it is possible to clear a bar higher than the jumperr's center of mass by using an appropriate jumping technique first used by Fosbury.
gH = V^2/2,
assuming yjat the initial velolcity V is UP.
Thus H = V^2/(2g) = 1.84 m = 6 ft 5 inches
The actual high jump world record is higher than that (about 8 feet)because the center of mass does not start at the ground, and because it is possible to clear a bar higher than the jumperr's center of mass by using an appropriate jumping technique first used by Fosbury.
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